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the sum of three consecutive even numbers is 48. what are the smallest of these numbers

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The example for consecutive even numbers is 2,4,6,8,10,. . . .
The above consecutive even number series  can be written as
        2,2+2,2+4,2+6,2+8,2+10, . . . . .
In the above series if we replace 2 in every number by “x”.
Then the above series can be rewritten as
        X, X+2,X+4,X+6, X+8, X+10, X+12,. . . . . . .
From the above series we can written as
2 consecutive even numbers = X, X+2
3 consecutive even numbers  =        X, X+2,X+4
4 consecutive even numbers =  X, X+2,X+4,X+6
5 consecutive even numbers =   X, X+2,X+4,X+6, X+8
Now we see the following problem
the sum of three consecutive even numbers  is 48. what is the smallest of these numbers
We can write three consecutive even number series as
 3 consecutive even numbers =   X, X+2,X+4.
   Sum of consecutive even numbers = X+ X+2+X+4
                                                              48=X+X+X+2+4
                                                              48= X+X+X+2+4
                                                             48= 3X+2+4
                                                             48=3X+6
                                                             48-6=3X
                                                             42=3X
It can be written as
                                                             3X=42
                                                               X= 42/3
                                                                  = 14
3 consecutive even numbers =   X, X+2,X+4
Substituting x =14
3 consecutive even numbers = 14, 14+2, 14+4
                                                    =   14, 16,18
from the above series smallest number = 14.
From the above series biggest number = 18.
the sum of three consecutive even numbers is 42  then the biggest of these numbers = 18.

the sum of three consecutive even numbers is 42  then the smallest of these numbers = 14.

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