find three consecutive even numbers whose sum is 468

The example for consecutive even numbers  is 2,4,6,8,10,. . . .

The above consecutive even number series  can be written as

        2,2+2,2+4,2+6,2+8,2+10, . . . . .

In the above series if we replace 2 in every number by “x”.

Then the above series can be rewritten as

        X, X+2,X+4,X+6, X+8, X+10, X+12,. . . . . . .

From the above series we can written as

2 consecutive even numbers = X, X+2

3 consecutive even numbers  =        X, X+2,X+4

4 consecutive even numbers =  X, X+2,X+4,X+6

5 consecutive even numbers =   X, X+2,X+4,X+6, X+8

Now we see the following problem

the sum of three consecutive even numbers is 468. what are those numbers

We can write three consecutive even number series as

 3 consecutive even numbers =   X, X+2,X+4.

   Sum of consecutive even numbers = X+ X+2+X+4

                                                              468=X+X+X+2+4

                                                              468= X+X+X+2+4

                                                             468= 3X+2+4

                                                             468=3X+6

                                                             468-6=3X

                                                             462=3X

It can be written as

                                                             3X=462

                                                               X= 462/3

                                                                  = 154

3 consecutive even numbers =   X, X+2,X+4

Substituting x =154

3 consecutive even numbers =154, 154+2,154+4

                                                    =  154, 156,158

from the above series smallest number =154.

From the above series biggest number = 158.

the sum of three consecutive even numbers is 468  then the biggest of these numbers = 158.

the sum of three consecutive even numbers is 468  then the smallest of these numbers = 154.