Skip to main content

multiples of 15

By
Multiplication  Table for 15    
15     x       1       =       15
15     x       2       =       30
15     x       3       =       45
15     x       4       =       60
15     x       5       =       75
15     x       6       =       90
15     x       7       =       105
15     x       8       =       120
15     x       9       =       135
15     x       10     =       150
15     x       11     =       165
15     x       12     =       180
15     x       13     =       195
15     x       14     =       210
15     x       15     =       225
15     x       16     =       240
15     x       17     =       255
15     x       18     =       270
15     x       19     =       285
15     x       20     =       300
As shown in the above multiplication table, multiples of 15 are

15,30,45,60,75,90,........ 


Remaining multiples from 15 to 750 are shown in the below table

15
30
45
60
75
90
105
120
135
150
165
180
195
210
225
240
255
270
285
300
315
330
345
360
375
390
405
420
435
450
465
480
495
510
525
540
555
570
585
600
615
630
645
660
675
690
705
720
735
750

Comments

Post a Comment

Popular posts from this blog

average of first 100 odd numbers

By
  Odd  numbers are 1,3,5,7,9,…. Average = sum of elements/  no  of elments Now we will see the sum of elements: Sum of first 2 odd  numbers: 1+3= 4= 2 2 Sum of first 3 odd  numbers: 1+3+5= 9= 3 2 Sum of first 4 odd  numbers: 1+3+5+7=16= 4 2 Sum of first 5 odd  numbers: 1+3+5+7+9 = 25 = 5 2 Sum of first n odd  numbers: 1+3+5+7+9+. . . . .  n numbers= n 2 Now we will see average: Average of first 2 odd numbers= (1+3)/2                                                           = 4/2                                                                 =2 Average of first 3 odd  numbers= (1+3+5)/3                                                           = 9/3                                                                 =3 Average of first 4 odd  numbers= (1+3+5+7)/4                                                           = 16/4                                                                 =4 Average of first 5 odd numbers= (1+3+5+7+9)/5            
1 comment
Read more

LOGIC BEHIND MAGIC SQUARE

By
Assume a magic square of 3x3 A B C D E F G H I The above figure shows a 3x3 magic square. In the magic square sum of colum, row, diagnol numbers should be same A+B+C=D+E+F=G+H+I=A+D+G=B+E+H=C+F+I=A+E+I=C+E+G=sum A+B+C D+E+F G+H+I A+D+G B+E+H C+F+I A+E+I C+E+G By  seeing the  above there is 8 type of sum is available. Row wise-3,  column wise-3, diagnol wise-2. Condition#1: There are 8 different combinations are there with same sum in a magic square. In the above 8 combinations A=2 times, B= 3 times, C= 2 times, D=3 times E=4 times, F=3 times, G=2 times, H=3 times, I= 2 times Hence the above forms the condition#2. In simply condition#2, middle number E appears 4 times in 8 combinations. Hence row, column, diagnol sum should be equal. In 3x3 magic square we are taking numbers from 1 to 9. From 9 numbers we need to take 3 numbers. From combination f
1 comment
Read more

average of first n natural numbers

By
The natural numbers are 1,2,3,4,5,. . . . . . now we will see the sum of natural numbers                       sum of first 3 natural numbers= 1+2+3=6 the above can be written as                      sum of first 3 natural numbers= 1+2+3=6=3(3+1)/2                      sum of first 4 natural numbers= 1+2+3+4=4(4+1)/2                      then sum of n natural numbers=1+2+3+......n terms=n(n+1)/2 then the average formula = sum of elements/no of elements                     the average of n natural numbers= sum of elements/ no of elements                                                                         =(n(n+1)/2)/n                                                                         =n(n+1)/2xn                                                                         =(n+1)/2   THE AVERAGE OF FIRST N NATURAL  NUMBERS=(n+1)/2 The average of first 5 natural numbers                                  sum of 5 natural numbers=1+2+3+4+5=15            
Post a Comment
Read more