clock problems with solution and answer

In ALL Competitive exams problem on clock are asking..

these are problems related to the clock problems with solution and answer.all the problems are

explained step by step procedure to understand very easily.

clock related problems with solutions are given below please click the following links

1. Angle between hour and minute hand at 12 30.

2.Angle between hour and minute hand at 11 30

3.Angle between hour and minute hand at 10 30

4.Angle between hour and minute hand at 9 30

5. Angle between hour and minute hand at 8 30

6.Angle between hour and minute hand at 7 30

7. Angle between hour and minute hand at 6 30

8.Angle between hour and minute hand at 5 30

9.Angle between hour and minute hand at 4 30

10. Angle between hour and minute hand at 3 30

11. Angle between hour and minute hand at 2 30

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average of first 100 odd numbers

Odd numbers are 1,3,5,7,9,…. Average = sum of elements/ no of elments Now we will see the sum of elements: Sum of first 2 odd numbers: 1+3= 4= 2 2 Sum of first 3 odd numbers: 1+3+5= 9= 3 2 Sum of first 4 odd numbers: 1+3+5+7=16= 4 2 Sum of first 5 odd numbers: 1+3+5+7+9 = 25 = 5 2 Sum of first n odd numbers: 1+3+5+7+9+. . . . . n numbers= n 2 Now we will see average: Average of first 2 odd numbers= (1+3)/2 = 4/2 =2 Average of first 3 odd numbers= (1+3+5)/3 = 9/3 =3 Average of first 4 odd numbers= (1+3+5+7)/4 = 16/4 =4 Average of first 5 odd numbers= (1+3+5+7+9)/5

LOGIC BEHIND MAGIC SQUARE

Assume a magic square of 3x3 A B C D E F G H I The above figure shows a 3x3 magic square. In the magic square sum of colum, row, diagnol numbers should be same A+B+C=D+E+F=G+H+I=A+D+G=B+E+H=C+F+I=A+E+I=C+E+G=sum A+B+C D+E+F G+H+I A+D+G B+E+H C+F+I A+E+I C+E+G By seeing the above there is 8 type of sum is available. Row wise-3, column wise-3, diagnol wise-2. Condition#1: There are 8 different combinations are there with same sum in a magic square. In the above 8 combinations A=2 times, B= 3 times, C= 2 times, D=3 times E=4 times, F=3 times, G=2 times, H=3 times, I= 2 times Hence the above forms the condition#2. In simply condition#2, middle number E appears 4 times in 8 combinations. Hence row, column, diagnol sum should be equal. In 3x3 magic square we are taking numbers from 1 to 9. From 9 numbers we need to take 3 numbers. From combination f

average of first n natural numbers

The natural numbers are 1,2,3,4,5,. . . . . . now we will see the sum of natural numbers sum of first 3 natural numbers= 1+2+3=6 the above can be written as sum of first 3 natural numbers= 1+2+3=6=3(3+1)/2 sum of first 4 natural numbers= 1+2+3+4=4(4+1)/2 then sum of n natural numbers=1+2+3+......n terms=n(n+1)/2 then the average formula = sum of elements/no of elements the average of n natural numbers= sum of elements/ no of elements =(n(n+1)/2)/n =n(n+1)/2xn =(n+1)/2 THE AVERAGE OF FIRST N NATURAL NUMBERS=(n+1)/2 The average of first 5 natural numbers sum of 5 natural numbers=1+2+3+4+5=15

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