Arithmetic1

Odd  numbers are 1,3,5,7,9,…. Now we will see the sum of elements: Sum of first 2 odd  numbers: 1+3= 4= 2 2 Sum of first 3 odd  numbers: 1+3+5= 9= 3 2 Sum of first 4 odd  numbers: 1+3+5+7=16= 4 2 Sum of first 5 odd  numbers: 1+3+5+7+9 = 25 = 5 2          Sum of first 6 odd  numbers: 1+3+5+7+9 +11= 36 = 6 2          Sum of first 7 odd  numbers: 1+3+5+7+9+11+13 = 49 = 7 2          Sum of first 8 odd  numbers: 1+3+5+7+9+11+13+15 = 64 = 8 2    Sum of first n odd  numbers: 1+3+5+7+9+. . . . .  n numbers= n 2

In a magic square 3x3, if we take numbers from 1 to 9 then the magic sum equal to 15. The magic square is as follows: 4 9 2  3 5 7 8 1 6 In the above magic square 3x3 magic sum is 15. In the above magic square 3x3 we are used numbers from1 to 9 arranged in 9 boxes. In any direction the sum equal to 15. Row wise  4+9+2=15, 3+5+7=15, 8+1+6=15. Column wise 4+3+8=15, 9+5+1=15, 2+7+6=15. Diagnol wise: 4+5+6=15, 2+5+8=15. The above magic square also can be written as follows: 5-1 5+4 5-3  5-2 5 5+2 5+3 5-4 5+1 In the above figure , shows the relation between middle number and other numbers. In the magic square we are taken numbers from 1 to 9 and number 5 is between 1 to 9. If we write  x in place of 5 in above magic square.                                         X-1 X+4 X-3  X-2 X X+2 X+3 X-4 X+1 Now we will write  magic square 3X3 with  magic sum=36  The magic sum is 33, means the middle number of

In a magic square 3x3, if we take numbers from 1 to 9 then the magic sum equal to 15. The magic square is as follows: 4 9 2  3 5 7 8 1 6 In the above magic square 3x3 magic sum is 15. In the above magic square 3x3 we are used numbers from1 to 9 arranged in 9 boxes. In any direction the sum equal to 15. Row wise  4+9+2=15, 3+5+7=15, 8+1+6=15. Column wise 4+3+8=15, 9+5+1=15, 2+7+6=15. Diagnol wise: 4+5+6=15, 2+5+8=15. The above magic square also can be written as follows: 5-1 5+4 5-3  5-2 5 5+2 5+3 5-4 5+1 In the above figure , shows the relation between middle number and other numbers. In the magic square we are taken numbers from 1 to 9 and number 5 is between 1 to 9. If we write  x in place of 5 in above magic square.                                         X-1 X+4 X-3  X-2 X X+2 X+3 X-4 X+1 Now we will write  magic square 3X3 with  magic sum=33  The magic sum is 33, means the middle number of m

The area of square is 289 sq units. The perimeter is.. Solution :     Formula for area of square = sidexside=289                            Assume side=x                                         XxX=289                                           X 2 =289                                           X=  √289                                         X=  √17x17                                        X=17 Perimeter of a square is 4xside of a square. Perimeter of a square= 4xside                                        =4x17                                       =68 sq unitis. The area of square is 196 sq units. The perimeter is..

The area of square is 121 sq units. The perimeter is.. Solution :     Formula for area of square = sidexside=121                            Assume side=x                                         XxX=121                                           X 2 =121                                           X=  √121                                         X=  √11x11                                        X=11 Perimeter of a square is 4xside of a square. Perimeter of a square= 4xside                                        =4x11                                       =44 sq unitis. The area of square is 196 sq units. The perimeter is..

The area of square is 144 sq units. The perimeter is.. Solution :     Formula for area of square = sidexside=144                            Assume side=x                                         XxX=144                                           X 2 =144                                           X=  √144                                         X=  √12x12                                        X=12 Perimeter of a square is 4xside of a square. Perimeter of a square= 4xside                                        =4x12                                       =48 sq unitis. The area of square is 196 sq units. The perimeter is..

The area of square is 169 sq units. The perimeter is.. Solution :     Formula for area of square = sidexside=169                            Assume side=x                                         XxX=169                                           X 2 =169                                           X=  √169                                         X=  √13x13                                        X=13 Perimeter of a square is 4xside of a square. Perimeter of a square= 4xside                                        =4x13                                       =52 sq unitis. The area of square is 196 sq units. The perimeter is..

The area of square is 196 sq units. The perimeter is.. Solution :     Formula for area of square = sidexside=196                            Assume side=x                                         XxX=196                                           X 2 =196                                           X=  √196                                         X=  √14x14                                        X=14 Perimeter of a square is 4xside of a square. Perimeter of a square= 4xside                                        =4x14                                       =56 sq unitis.

The area of square is 256 sq units. The perimeter is.. Solution :     Formula for area of square = sidexside=256                            Assume side=x                                         XxX=256                                           X 2 =256                                           X=  √256                                         X=  √16x16                                        X=16 Perimeter of a square is 4xside of a square. Perimeter of a square= 4xside                                        =4x16                                       =64 sq unitis.